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Question

(A) Let the distance between point $A$ and point $B$ be $d$.Time taken to travel from $A$ to $B$ is $t_1 = \frac{d}{v_1} = \frac{d}{40}$.Time taken to

Vedclass · Accepted Answer

$48$

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(A) Let the distance between point $A$ and point $B$ be $d$.Time taken to travel from $A$ to $B$ is $t_1 = \frac{d}{v_1} = \frac{d}{40}$.Time taken to travel from $B$ to $A$ is $t_2 = \frac{d}{v_2} = \frac{d}{60}$.Total distance covered = $d + d = 2d$.Total time taken = $t_1 + t_2 = \frac{d}{40} + \frac{d}{60} = \frac{3d + 2d}{120} = \frac{5d}{120} = \frac{d}{24}$.Average speed = $\frac{	ext{Total distance}}{	ext{Total time}} = \frac{2d}{d/24} = 2 	imes 24 = 48 \ km/h$.

$A$ car travels from point $A$ to point $B$ with a speed of $40 \ km/h$ and returns from $B$ to $A$ with a speed of $60 \ km/h$. What is the average speed of the car for the entire journey (in $km/h$)?

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